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3 years ago

14

Sophie bikes at a speed of s miles per hour. her friend rana is slower, her biking speed is only r miles per hour. Tomorrow both

girls are planning to spend 3 hours biking. how much longer will be the sophies route

1 answer:

rjkz [21]3 years ago

4 0

36 hrs and 21 mins hope that is ok

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If the r-value, or correlation coefficient, of a data set is negative , the coefficient of determination is negative

AleksAgata [21]

This is false because the confection of a determination is native

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1 year ago

A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes

Anvisha [2.4K]

Answer:

Probability will be 0.5779

Step-by-step explanation:

Number of tablets n = 19

Probability of defect rems that is p = 0.03

Here number of trials is fixed and probability of success = 0.03

Here p = 0.03

So q = 1 - p = 1 -0.03 = 0.97

By using binomial distribution

Probability is given by $^nC_rp^rq^{n-r}$

So P(0 or 1) = $^{19}C_0{0.03}^0{0.97}^{19-0}+^{19}C_1{0.03}^1{0.97}^{19-1}=0.5606+0.0173=0.5779$

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3 years ago

What is the measure of an angel that turns through 3/4 of a complete circle?

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2/3 think of this as a pie right divided into 3 area but only 2 people eat from it 1 left but how would i complete it if its not done well i need to complete the "pie"
by adding an exponent into the mesure and cacultating a mass of a=mx+b
now you divide and get 0.75
so you will fill in .25 more to get the full measurement by eating 1 more pie:

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3 years ago

A right circular cylinder has a radius of 5 inches and a height of 10 inches. what is its volume?

Aloiza [94]

V=πr2h

v=π(5)^2(10)

v=250π

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3 years ago

Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?

9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

$f(x)=\frac{(x-1)(x^2-4)}{x^2-a}$

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that $x=\sqrt{a}$ will annulate the denominator, i.e

$(\sqrt{a})^2-a = a-a = 0$ . But, if a = 1 we have:

$f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}$

so, the value $x=\sqrt{a} = \sqrt{1} = 1$ won't annulate the denominator.

Now, for a = 4 we have:

$f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1$

so, the value $x=\sqrt{a} = \sqrt{4} = 2$ won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0

3 years ago