Question

PLEASE ANSWER ASAP! YOUR ANSWER MUST REQUIRE AN EXPLANATION IN ORDER TO RECEIVE 10 POINTS AND THE BRAINLIEST ANSWER!!! THANKS!!!!

Answer 1

Hello,

Using vectors and scalar product:

$[(a+c)*\vec{i}+(b-0)*\vec{j} ].[(a-c)*\vec{i}+(b-0)*\vec{j}]=0$
Thus
$\dfrac{b^2}{(a+c)(a-c)}=1$

By the way how can we make text larger in latex \larger{.....} don't work.

Answer A