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3 years ago

1/9x^2-4 Decomposition

Mathematics

1 answer:

irina [24]3 years ago

8 0

I got 0.01298?
(probably wrong)

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It takes Jill 2 hours to run 14.5 miles. At this rate, how far can she run in 3 hours?

Semmy [17]

Answer:

21.75

Step-by-step explanation:

14.50 divide-by 2 = 7.25 so 14.50 + 7.25= 21.75

8 0

3 years ago

Read 2 more answers

3s(4+6)^2 is an example of

mr_godi [17]

Answer:

the answer for this is D.

Step-by-step explanation:

it is a combination of letters operations and variables.But it is not equated (=) to something that is why it is not an algebraic equation.It is also not a numerical equation or numerical expression because it does not consist of only numbers.

7 0

3 years ago

Distance Formula D=√(x2-x1)² + (y2 - y₁) ² a. 8.149 b. 8.84 c. 9.438 d.12.369

lakkis [162]

Answer:

Step-by-step explanation:

using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (- 2, 4 ) and (x₂, y₂ ) = (10, 1 )

d = $\sqrt{10-(-2))^2+(1-4)^2}$

= $\sqrt{(10+2)^2+(-3)^2}$

= $\sqrt{12^2+9}$

= $\sqrt{144+9}$

= $\sqrt{153}$

≈ 12.369

5 0

2 years ago

Cuanto cuestan 4 camisetas a $16,000 la docena?

Y_Kistochka [10]

<span>Lo siento, no sé español, pero lo intenté.

Si se trata de "$ 16,000" para una docena de camisas que es 12, se dividiría "16,000 entre 12". Luego obtendrás 1,333.3 para multiplicar eso por 4 y luego obtendrás 5,333.3 a lo que responderás.

Esta es la ecuación,
16,000 / 12 = 1,333.3 x 4 = 5,333.3

Espero que esto ayude :-)</span>

4 0

4 years ago

Write the equation of a circle for which the endpoints of a diameter are (-2,-2) and (4,-10)

Maurinko [17]

Answer:

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

Step-by-step explanation:

Given:

End point of Diameter be

point A( x₁ , y₁) ≡ ( -2 ,-2 )

point B( x₂ , y₂) ≡ ( 4 , -10 )

To Find:

Equation of a circle =?

Solution:

When end points of the Diameter are A( x₁ , y₁) , B( x₂ , y₂). then the Equation of Circle is given as

$(x-x_{1})(x-x_{2})+(y-y_{1})(y-y_{2})=0$

Substituting the end point are

$(x-(-2))(x-4)+(y-(-2))(y-(-10))=0\\(x+2))(x-4)+(y+2))(y+10))=0\\$

Applying Distributive Property we get

$x^{2} -2x-8+y^{2}+12y+20 =0\\\\x^{2}+y^{2}-2x+12y+12=0$

Therefore the required Equation of Circle

$x^{2}+y^{2}-2x+12y+12=0$

6 0

3 years ago