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2 years ago

9

an arts academy requires there to be 3 teachers for every 51 students and 5 tutors for every 45 students. how many students does

the academy have per teacher? per tutor? how many tutors does the academy need if it has 90 students? The academy has ___ students per tutor

1 answer:

padilas [110]2 years ago

6 0

Answer:

17 students per teacher, 9 students per tutor. You need 10 tutors if the school had 90 students.

Step-by-step explanation:

51 students divided by 3 teachers = 17 students per teacher.

45 students divided by 5 tutors = 9 students per teacher.

If there are 9 students per tutor 9 * 10 = 90 so ten tutors

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If x=5^a, find the value of 5x. How?

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$5x = 5^{(a+1)}$

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Here is a problem with the concept of properties of the exponent.

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2 years ago

The product of two numbers is 161 , one of number is 7,find the other number.

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2 years ago

Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from B, a distance o

g100num [7]

Answer:

The value is $k =109.6 \ miles$

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

The distance from city A to B is AB = 467.3 miles

The bearing from B to C is $\theta_{BC} = N 28.7E$

The bearing from B to A is $\theta_{BA} = N 60.7E$

The bearing from A to B is $\theta_{AB} = S60.7W$

The bearing from A to C is $\theta_{AC} = S79.1W$

Generally from the diagram

$\theta_A = 180 - 60.7 -79.1$

=> $\theta_A = 40.2 ^o$

Also

$\theta_B = 32^o$

and

$\theta_C = 180 - (\theta_A +\theta_B )$

=> $\theta_C = 180 - (40.2 + 32 )$

=> $\theta_C = 107.8 ^o$

Generally according to Sine Rule

$\frac{BC}{sin (\theta_A)} = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}$

=> $\frac{BC}{sin (40.2)} = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}$

So

$\frac{BC}{sin (40.2)} = \frac{467.3 }{sin (107.8)}$

=> $BC = 316.8 \ miles$

Also

$\frac{CA}{sin (32)} = \frac{467.3 }{sin (107.8)}$

$CA = 260 .1 \ miles$

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct flight is mathematically represented as

$k = [CA +BC] - AB$

=> $k = [260 .1 +316.8]- 467.3$

=> $k =109.6 \ miles$

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2 years ago