I believe the answer is A
Answer:
m<BAC = 34
Step-by-step explanation:
It is given that (<BOC) is a central angle with a degree measure of (68). A central angle is an angle whose vertex is the center of the circle. (<BAC) is an inscribed angle, an angle whose vertex is on the circumference (perimeter) of the circle. Arc (BC) connects the ends of both of these angles.
The central angle theorem states that the measure of the central angle is equivalent to its surrounding arc. Using this theorem, one can state the following,
m<BOC = BC = 68
The inscribe angle theorem states that the measure of the arc surrounding the inscribed angle is twice the measure of the inscribed angle. Applying this theorem, one can state the following,
2(m<BAC) = (BC)
2 (m<BAC) = 68
m<BAC = 34
114
1^3 + 1^3 + 4^3 = 1 + 1 + 64 = 66
99 - 66 = 33
33/3 = 11
1 + 1 = 2
I am not sure of the exact way to solve this....I just did it by trial and error
Answer:
x=-16
Step-by-step explanation:
6x - 2y = 14
-7x + 2y = 2
