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VikaD [51]
3 years ago
6

FRUIT

Mathematics
1 answer:
laiz [17]3 years ago
5 0
2p+6a=$14
3p+9a=$21

3p+9a=21
Subtract 9a
3p=21-9a
divide all by 3
p=7-3a
plug it into start equations

2p+6a=14
2(7-3a)+6a=14
14-6a....+6a=14

this zeroes out...
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Find Endpoint from Midpoint and Endpoint
erastova [34]

Answer:

The endpoint, B, is (-7, -8)

Step-by-step explanation:

When I get a problem like this, the first thing I like to do is find the difference between the midpoint and the starting point.

In this problem it would be -5 - -3 = -2 and -2 - 4 = -6.

(-2, -6) is what will help us find the endpoint.

Take the midpoint, (-5, -2), and add those coordinates to it.

-5 + -2 = -7

-2 + -6 = -8

So our endpoint is (-7, -8)

Here is a graph, to help you visualize it.

5 0
2 years ago
Rhombus ABCD has vertices at (-6, 0),(0,8), (6,0), and (0, -8).
SVETLANKA909090 [29]
A’ -9,0. B’ 0,12. C’ 9,0. D’ 0, -12. As long as u put the in order when u listed them that’s the way I put them.
5 0
3 years ago
0.001y^12, <br> 0.008b^6,<br> -8/27a^15 <br> Written as a cube of a monomial.
Tomtit [17]

0.001y^{12}=(0.1)^3y^{4\cdot3}=(0.1)^3(y^4)^3=(0.1y^4)^3\\\\0.008b^6=(0.2)^3b^{2\cdot3}=(0.2)^3(b^2)^3=(0.2b^2)^3\\\\-\dfrac{2}{27}a^{15}=\left(-\dfrac{2}{3}\right)^3a^{5\cdot3}=\left(-\dfrac{2}{3}\right)^3(a^5)^3=\left(-\dfrac{2}{3}a^5\right)^3\\\\\text{Used:}\\\\(a^n)^m=a^{n\cdot m}\\\\(ab)^n=a^nb^n

5 0
4 years ago
What is the correct meaning of the word commit?
Goshia [24]

Answer:

Achieve

Step-by-step explanation:

Ana will achieve ten hours to volunterring each week.

8 0
3 years ago
Read 2 more answers
a new car is purchased for 207000 dollars. the value of the car depreciates at 11% per year. what will the value of the car be,
kicyunya [14]
Depreciation of 11% per year means that the price is multiplied by 89% (0.89) every year. Do this 11 times or use exponents

Final price:
207000*(0.89^11) = 57446.083
7 0
3 years ago
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