The cattle train
speed - 36.5 km/h
time - x h
the passenger train
speed - 29.2 km/h
time - (2.4+x) h
The cattle train caught up to the passenger train so the distance they travelled is the same.
Distance is speed times time.

The passenger train travelled for
12 hours before the cattle train caught up.
You'll need to isolate 9a on the left side of this equation
Please add 7 to both sides of the eqn, obtaining 9a = 117.
Solve for a by dividing both sides by 9: a = 117/9 = 13 (answer)
Answer:
x=0
Step-by-step explanation:
R = dfrac3 t-1 + t. Brainliest please?