Answer:
Henry will get $15.77 back.
Step-by-step explanation:
20 - 4.23 = 15.77
I had the same question on my hw and I picked c \(“-)/
Volume of water in the tank:
![V=\pi (2\,\mathrm m)^2h=\pi(200\,\mathrm{cm})^2h](https://tex.z-dn.net/?f=V%3D%5Cpi%20%282%5C%2C%5Cmathrm%20m%29%5E2h%3D%5Cpi%28200%5C%2C%5Cmathrm%7Bcm%7D%29%5E2h)
Differentiate both sides with respect to time <em>t</em> :
![\dfrac{\mathrm dV}{\mathrm dt}=\pi(200\,\mathrm{cm})^2\dfrac{\mathrm dh}{\mathrm dt}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20dV%7D%7B%5Cmathrm%20dt%7D%3D%5Cpi%28200%5C%2C%5Cmathrm%7Bcm%7D%29%5E2%5Cdfrac%7B%5Cmathrm%20dh%7D%7B%5Cmathrm%20dt%7D)
<em>V</em> changes at a rate of 2000 cc/min (cubic cm per minute); use this to solve for d<em>h</em>/d<em>t</em> :
![2000\dfrac{\mathrm{cm}^3}{\rm min}=\pi(40,000\,\mathrm{cm}^2)\dfrac{\mathrm dh}{\mathrm dt}](https://tex.z-dn.net/?f=2000%5Cdfrac%7B%5Cmathrm%7Bcm%7D%5E3%7D%7B%5Crm%20min%7D%3D%5Cpi%2840%2C000%5C%2C%5Cmathrm%7Bcm%7D%5E2%29%5Cdfrac%7B%5Cmathrm%20dh%7D%7B%5Cmathrm%20dt%7D)
![\dfrac{\mathrm dh}{\mathrm dt}=\dfrac{2000}{40,000\pi}\dfrac{\rm cm}{\rm min}=\dfrac1{20\pi}\dfrac{\rm cm}{\rm min}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20dh%7D%7B%5Cmathrm%20dt%7D%3D%5Cdfrac%7B2000%7D%7B40%2C000%5Cpi%7D%5Cdfrac%7B%5Crm%20cm%7D%7B%5Crm%20min%7D%3D%5Cdfrac1%7B20%5Cpi%7D%5Cdfrac%7B%5Crm%20cm%7D%7B%5Crm%20min%7D)
(The question asks how the height changes at the exact moment the height is 50 cm, but this info is a red herring because the rate of change is constant.)
Where is the problem so that I may be able to help you??
Answer:
y=mx+b where m is slope and b is y int
Step-by-step explanation:
1) slope 1/4 and yint 8
2) slope -2 and yint -3
3)slope 0 and y -int is 0 when there is no b
4) Slope is 0 and y int is 7 when there is no B