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lisabon 2012 [21]
3 years ago
15

What is x in 2c-3=12-2c+7c

Mathematics
1 answer:
Eduardwww [97]3 years ago
7 0

Answer:

c=-5

Step-by-step explanation:

2c-3=12-2c+7c

2c-3=12+5c

2c-5c-3=12

-3c-3=12

-3c=12+3

-3c=15

c=15/-3

c=-5

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If the radius of a coin is 20cm ,find its surface area.​
jasenka [17]

Answer:

It's surface area is 1257.14cm^2

Step-by-step explanation:

area=22/7×20cm×20cm

=3.14×20cm×20cm

=1257.14cm^2

4 0
3 years ago
Which number is not in the solution set up X - 8 < 14
Sergeu [11.5K]

Answer:

x < 22

Step-by-step explanation:

X - 8 < 14

Add x to each side

X - 8+8 < 14+8

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3 0
3 years ago
Read 2 more answers
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

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3 years ago
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77julia77 [94]

Answer:

The answer is A)

Step-by-step explanation:

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<em>Hope this helps!</em>

3 0
2 years ago
The product of b and 6 decreased by 2
Ivanshal [37]

Answer:

6b - 2

Step-by-step explanation:

Product of b and 6 : b*6 = 6b

6b decreased by 2:       6b - 2

6 0
3 years ago
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