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tino4ka555 [31]
3 years ago
11

10. Amina is currently twice as old as her younger brother,

Mathematics
1 answer:
maks197457 [2]3 years ago
6 0

Answer:

When Amina is 18. Saad would be;

k. 14

Step-by-step explanation:

Let "x" represent Anita's current age and let "y" represent Saad's current age, we have;

Anita's age = 2 × Saad's age

Therefore;

x = 2 × y...(1)

In 4 years, we will get;

x + 4  = 1.5 × (y + 4)...(2)

Substituting the value of x in equation (1) into equation (2), we get;

2·y + 4 = 1.5·y + 1.5 × 4 = 1.5·y + 6

2·y + 4 = 1.5·y + 6

2·y - 1.5·y   = 6 - 4 = 2

0.5·y = 2

y = 2/0.5 = 4

Saad's current age = y = 4 years

From equation (1), we have;

x = 2 × y = 2 × 4 = 8

Amina's current age = x = 8 years

When Amina is 18, we have;

18 = 10 + 8 = 10 + x

Therefore, Amina would be 18 in 10 years time from now, from which we have;

Saad would be 10 years + y = 10 years + 4 years = 14 years in 10 years from now

Therefore, when Amina would be 18 years in 10 years from now Saad would be 14 years.

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