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3 years ago

Please answer, I will give brainliest

Mathematics

1 answer:

irga5000 [103]3 years ago

7 0

Step-by-step explanation:

Hey, there!!

Let's look in your question,

Firstly Mr.Ingerson was in Ghana and bought it in 35000 cedi for a djembedrum.

At that time 1 US dollar= 7000 Cedi.

He paid 35000 cedi.

Us dollar for 35000 cedi = 35000/7000 $.

So, he had bought it in $5.

now,

At present,

The value of 1$ is 5.79 cedi.

As he bought it on same value,

5$ is equal to 5.79×5

= 28.95 cedi.

{ here, as it told that it was bought in same value its value is $5 only but, as the value of $ will be changed into 5.79}.

Hope it helps...

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Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

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$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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