Answer:
AC = 127,26 f distance from home plate to second base
Step-by-step explanation:
Let call A , B , C Home plate, first base and second base respectively
These three point form a right triangle with legs ( AB = BC = 90 feet)
we have an isosceles triangle with a right angle and two angles of 45⁰
So we need to compute distance AC (hypotenuse)
AC² = AB² + BC² ⇒ AC² = 2AB² ⇒ AC = AB √2
AC = 90 * 1,414
AC = 127,26 f
Black line m = -1/2 b = 2
blue line m = 1/3 b = -3
green line m = 2 b = 1/2
hope this helps.......
Answer:
good job.
Step-by-step explanation:
