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devlian [24]
3 years ago
7

You and your family left the house for a vacation at 8 A.M. You promptly fell asleep in the

Mathematics
2 answers:
poizon [28]3 years ago
8 0

Answer:

201 miles.

Step-by-step explanation:

If you've traveled 124 miles in 2 hours, than in one hour must've been 62 miles. 62 multiplied by 3 is 186, which is how much miles have been traveled in 3 hours. Plus the 15 minutes would probably be 201 miles. Hope this helps!

Misha Larkins [42]3 years ago
4 0
Answer is the miles times speed I think
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Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of
ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is A(t) = 810(0.74)^t

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

A(t) = A(0)(1-r)^t

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that A(24) = (1-0.26)A(0) = 0.74A(0); We use this to find r.

A(t) = A(0)(1-r)^t

0.74A(0) = A(0)(1-r)^{24}

(1-r)^{24} = 0.74

\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}

1 - r = (0.74)^{\frac{1}{24}}

1 - r = 0.9875

r = 1 - 0.9875 = 0.0125

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that A(0) = 810

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

A(t) = A(0)(1-r)^t

A(t) = 810(1 - 0.26)^t

A(t) = 810(0.74)^t

The function to represent the mass of the sample after t days is A(t) = 810(0.74)^t

5 0
3 years ago
Find the numerical value of the log expression. \log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3 loga=7logb=10logc=3 \log \
bija089 [108]

Answer:

  32

Step-by-step explanation:

  \log a=7\hspace{15px} \log b=10\hspace{15px} \log c=3\\\\ \log \dfrac{a^8c^2}{b^3}=8\log{a}+2\log{c}-3\log{b}=(8)(7)+(2)(3)-(3)(10)\\\\=56+6-30=\boxed{32}

__

The applicable rules of logarithms are ...

  log(ab/c) = log(a) +log(b) -log(c)

  log(a^b) = b·log(a)

6 0
3 years ago
Evaluate the expression, when x = 3.2x + 4(x - 2)a910ObocOd118
love history [14]

The initial expression is:

2x + 4(x - 2)

Replacing x by 3, we get:

2(3) + 4(3 - 2)

6 + 4(1)

6 + 4

10

The value of the expression is 10

4 0
1 year ago
X2 + 13x = -22 solve for x
aliya0001 [1]
I believe the answer would be -2 and -11 hope this helped!
3 0
3 years ago
Explain (in words) what you would do to find the missing value in the equation. You do not find the missing number! Equation: ?
maks197457 [2]

Answer:

The missing value = 23\frac{1}{24}

Step-by-step explanation:

Given - Equation: ? + 59 5/8= 82 2/3

To find - Explain (in words) what you would do to find the missing value in

              the equation. You do not find the missing number.

Proof -

Let the missing number = x

So, the equation becomes x + 59\frac{5}{8} = 82\frac{2}{3}

⇒x = 82\frac{2}{3} - 59\frac{5}{8}

     = \frac{248}{3} - \frac{477}{8}

     = \frac{1984 - 1431}{24}

     = \frac{553}{24}

     = 23\frac{1}{24}

⇒x = 23\frac{1}{24}

∴ we get

The missing value = 23\frac{1}{24}

Explanation -

Here we have given the ? with addition of number that is equation to some number.

We just have to subtract the two numbers to find the missing value , as we do above.

5 0
2 years ago
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