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Pepsi [2]
3 years ago
7

V^2+3v-5=0 Round to nearest hundredth

Mathematics
1 answer:
natulia [17]3 years ago
6 0
V² + 3v - 5 = 0
v = -(3) ± √((3)² - 4(1)(-5))
                    2(1)
v = -3 ± √(9 + 20)
                2
v = -3 ± √(29)
            2
v = -3 ± 5.38
            2
v = -1.5 ± 2.69
v = -1.5 + 2.69    or    v = -1.5 - 2.69
v = 1.19    or    v = -3.19
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chubhunter [2.5K]
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PLEASE HELP MEE!! IVE BEEN DOING THIS ASSIGNMENT FOR OVER 2 HOURS NOW, PLS HELP.. :(
Lesechka [4]

Answer:

x = -3, y = 5

Step-by-step explanation:

first, take the 3x + 17 = y and put it in place for the y in the second equation.

-3x=4x+17+4

then, solve the equation.

-3x=4x+21

-3x-4x=4x-4x+21

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-7/-7x=21/-7

x = -3

substitute in other equation

4(-3) + 17 = y

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answers are x = -3 and y = 5

5 0
3 years ago
Read 2 more answers
1. Mrs. Verner's class has
Gemiola [76]

Answer:

46.7%

Step-by-step explanation:

Given:

Total number of students in Mrs. Verner's class = 15

Number of girls = 8

To find: percentage are boys

Solution:

Percentage of boys = ( Number of boys / Total number of students ) × 100

Number of boys = Total number of students - Number of girls = 15 - 8 = 7

So,

Percentage of boys =  × 100 = 46.7%

4 0
2 years ago
The accompanying table shows the number of bacteria present in a certain culture over a 4 hour period, where x is the time, in h
Vlad [161]

Answer:

Step-by-step explanation:

I really hope you know how to use your calculator to find regression equations, because in this forum it is impossible to teach you how to do that. I ran the data through my calculator and got the exponential equation as

y=1963.56(1.14)^x which means at 4 hours, we started with 1963 bacteria and it is growing at a rate of 114% each hour. Since we started out with an x value of 0, and that value represents the number of bacteria after 4 hours, then time 0 is 4 hours, which means that time 12 is 16 hours. We replace the x in the equation with a 12 and do the math:

y=1963.56(1.14)^{12 which gives us, in the end,

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4 0
3 years ago
The teachers of the two classes want to compare the heights of their students. Which statements about the data sets are accurate
aleksandr82 [10.1K]

This question is incomplete.

Complete question

The sets of data below show the heights, in inches, of students in two different preschool classes.

A) a box plot titled class 1.

The number line goes from 38 to 49. the whiskers range from 39 to 48, and the box ranges from 40 to 43. a line divides the box at 41.

class 1

B) A box plot titled class 2.

The number line goes from 38 to 49. the whiskers range from 38 to 49, and the box ranges from 39 to 42. a line divides the box at 41.

class 2

The teachers of the two classes want to compare the heights of their students. Which statements about the data sets are accurate? Select three options.

• Because the sets are symmetrical, the mean should be used to compare the data sets.

• Because the sets do not contain outliers, the MAD should be used to compare the data sets.

•Because the sets are not symmetrical, the IQR should be used to compare the data sets.

•Because the sets contain outliers, the median should be used to compare the data sets.

•The mean and mode cannot be accurately determined based on the type of data display.

Answer:

• Because the sets are not symmetrical, the IQR should be used to compare the data sets.

• Because the sets contain outliers, the median should be used to compare the data sets.

• The mean and mode cannot be accurately determined based on the type of data display.

Step-by-step explanation:

In the above question, we can see that a teacher intends to compare the heights of students from two different classes.

Because the data sets to be obtained would contain heights from different classes the results obtained would be non symmetrical.

Hence the best statistical analysis to use to solve for or to compare a set of non symmetrical data is known as either the Median or an Interquartile range.

It is important to note that a non symmetrical data would most likely contain or include the presence of outliers.

8 0
3 years ago
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