<h2>
Answer:</h2><h2>
The cost of an advance ticket = $40</h2><h2>
The cost of an same day ticket = $30</h2>
Step-by-step explanation:
There are two types of tickets to a show, advance and same day tickets.
Let the advance ticket be represented as x and same day ticket as y.
The combined cost of one advance ticket and one same-day ticket is $70.
x + y = 70 .... (1)
For one performance 35 Advance tickets and 25 same day tickets were sold the total amount paid for the ticket was 2150
35 x + 25 y = 2150 ... (2)
multiply eq (1) by 25, we get
25 x + 25 y = 1750 ... (3)
subtract eq (3) from (2), we get
10 x = 400,
x = 40, substitute in eq (1)
40 + y = 70
y = 30
The cost of an advance ticket = $40
The cost of an same day ticket = $30
Answer:
3/4
Step-by-step explanation:
Due it having a ratio of .75 instead of the .6875 of the other answers.
Answer:
7x + 6 =8x - 6
x= 12
Step-by-step explanation:
- put them equal to each other
- then subtract 8x from both sides
- 7x(-8x) + 6 = 8x(-8x) - 6
- to get -1x
- then subtract 6 from both sides
- you'll get -1x = -12
- then divide -1 to both sides
- then you get x = 12
Answer:
use this formula:
1 degree=pie/180
1)0 degree=pie/180 x0 =0
2)30 degree=pie/180 x30=pie/6
now do like this as above mentioned.
Answer:
someone was already answering it so there it is below
6 1/6
Step-by-step explanation:
(9-3)+(7/15-3/10)
subtract the numbers
6+(7/15-3/10)
6+1/6
6 1/6