The answer is D. Angle 4 and angle 8 are corresponding...
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
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I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer is D) 2/3 because you divide the whole equation by 3 scene as 2cups=3gal. In order to get one gal, you need to divide the right side by 3 to make one and what you do to one side of an equation, you must do to the other.
