Answer:
Step-by-step explanation:
Answer:
The maximum height of the ball is 256m
Step-by-step explanation:
Given the equation of a pathway modelled as pathway can be modeled by h = -16t² + 128t
At maximum height, the velocity of the ball is zero.
velocity = dh/dt
velocity = -32t + 128
Since v = 0 at maximum height
0 = -32t+128
32t = 128
t = 128/32
t = 4seconds
The maximum height can be gotten by substituting t = 4 into the modelled equation.
h = -16t² + 128t
h = -16(4)²+128(4)
h = -16(16)+512
h = -256+512
h = 256m
Answer:
Step-by-step explanation:
<h3>Given</h3>
<u>Quadratic function </u>
with the roots:
<h3>To find </h3>
<h3>Solution</h3>
<u>As we know the sum of the roots is -b/a and the product of the roots is c/a. Substituting values and solving for b and c:</u>
- (-5 + 9i) + (-5 - 9i) = -b/-1
- -10 = b
- b = -10
And
- (-5 + 9i)(-5 - 9i) = c/-1
- (-5)² - (9i)² = -c
- 25 - 81(-1) = -c
- - c = 25 + 81
- - c = 106
- c = -106
g(x) = -x² -10x - 106
(3,-1)? i believe that's what it would be
Answer:
The area of the trapezoid is 56 sq ft
