Answer: Please find below the answer along with explanation.
Explanation:
For a given communication channel (for instance, a LAN segment using Ethernet ) the Bandwidth refers to the theoretical maximum data rate that the channel can support, for instance, 100 Mbps in a 100Base T network.
The throughput, instead, refers to the actual data rate achieved in a given communications channel, taking into account the different channel impairments.
For instance, in a LAN segment that uses the original Ethernet 802.3 standard (CSMA/CD), a frequent occurrence of collisions can take down the actual data rate from the theoretical 100 Mbps to a very lower figure, i.e., 5 Mbps.
Answer:
files can easily infect your computer with viruses or malware.
Explanation:
Answer:
Constructor issue
Explanation:
When you look at the Class A, the constructor takes one argument as a parameter, a String.
A(String newS) {
s = newS;
}
However, in the main, the constructor does not take any argument as a parameter.
A a = new A();
That's why the code does not compile.
a. speed + 12 - miles * 2 = 10 + 12 - 5 * 2. With order of operations, we do the multiplication first so the equation is now 10 + 12 - 10 = 22 - 10 = 12
b. speed + miles * 3 = 10 + 5 * 3 and again, order of operations gives us 10 + 15 = 25
c. (speed + miles) * 3 = (10 + 5) * 3 = 15 * 3 = 45
d. speed + speed * miles + miles = 10 + 10 * 5 + 5 = 10 + 50 + 5 = 60 + 5 = 65
e. (10 – speed) + miles / miles = (10 - 10) + 5 / 5 = 0 + 5 / 5 = 5 / 5 = 1
