1. 12*100 - 12*5
You would use the distributive property to get this equation (it is equivalent to the original one)
2. Um... There's no actual story for this problem; sorry I can't solve this problem
Answer:
11.1 times
Step-by-step explanation:
The relevant rules of exponents are
.. (t^a)^b = t^(a·b)
.. t^a·t^b = t^(a+b)
You have
.. (t^-4)^-9·t^2
.. = t^((-4)*(-9) +2)
.. = t^38 . . . . . . . . . . . selection C
Answer:
Step-by-step explanation:
Mixture problems are really easy because the table never varies from one problem to another and they don't have a lot of variations in them like motion problems do. The table for us will look like this, using T for Terraza coffee and K for Kona:
#lbs x $/lb = Total
T
K
Mix
Now we just have to fill this table in using the info given. We are told that T coffee is $9 per pound, and that K coffee is $13.50 per pound, so we will fill that in first:
#lbs x $/lb = Total
T 9
K 13.50
Mix
Next we are told that the mix is to be 50 pounds that will sell for $9.54 per pound
#lbs x $/lb = Total
T 9
K 13.50
Mix 50 9.54
Now the last thing we have to have to fill in this table is what goes in the first column in rows 1 and 2. If we need a mix of 50 pounds of both coffees and we don't know how many pounds of each to use, then under T we have x and under K we have 50 - x. Notice along the top we have that the method to use to solve this problem is to multiply the #lbs by the cost per pound, and that is equal to the Total. So we'll do that too:
#lbs x $/lb = Total
T x x 9 = 9x
K 50 - x x 13.50 = 675 - 13.50x
Mix 50 x 9.54 = 477
The last column is the one we focus on. We add the total of T to the total of K and set it equal to the total Mix:
9x + 675 - 13.5x = 477 and
-4.5x = -198 so
x = 44 pounds. This means that the distributor needs to mix 44 pounds of T coffee with 6 pounds of K coffee to get the mix he wants and to sell that mix for $9.54 per pound.
