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OLEGan [10]
3 years ago
7

Why is .9 repeating NOT equal to one.

Mathematics
2 answers:
boyakko [2]3 years ago
8 0
Because infedecimals. Basically 1 -.99999.... Is a number so close to zero it is impossible to define. If this were infanct the case however and a number existed that was not 0 and not 0 it would wreck mathematics so infedecimals exist only theoretically. So .999... Is equal to 1 practically but not theoretically.
WARRIOR [948]3 years ago
8 0

Answer:

Step-by-step explanation:i agree with her

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Answer:

t = 0

Step-by-step explanation:

(7t - 2) - (-3t + 1) = -3(1 - 3t)

because you can not do anything inside the parantheses, you distribute. there aren't any numbers on the left side of the parantheses on the left side of the equation so we just imagine the number 1. on the right side of the equation, just distribute normally

[ 1(7t - 2) -1(-3t + 1) = -3(1 - 3t) ]

will be

7t - 2 + 3t - 1 = -3 + 9t

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Step 1) Draw a dashed line through the points (0,6) and (4,7). These two points are on the line y = (1/4)x+6. To find those points, you plug in x = 0 to get y = 6. Similarly, plug in x = 4 to get y = 7. The dashed line indicates that none of the points on this line are part of the solution set.

Step 2) Draw a dashed line through (0,-1) and (1,1). These two points are on the line y = 2x-1. They are found in a similar fashion as done in step 1. 

Step 3) Shade the region that is above both dashed lines. We shade above because of the "greater than" sign. This is shown in the attached image I am providing below. The red shaded region represents all of the possible points that are the solution set. Once again, any point on the dashed line is not in the solution set. 

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