3 years ago

Cot²θ+1 = -2 cotθ Solve the equation for 0≤θ< 2π

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

7 0

Answer:

Step-by-step explanation:

haha thanks for the points!

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3 years ago

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(1) What is the equation, in point-slope form, for a line that goes through (8, −4) and has a slope of negative 5/6 (all fractio

Andreyy89

Formula for point-slope: $y - y1 = m(x-x1)$
Plug in the values (1): $y + 4 = -\frac{5}{6} (x - 8)$ {Choice B}
Plug in the values (2): $y + 6 = \frac{1}{3}(x+ 2)$ {Choice C}
_______________________

[For (3) and (4) we need to solve for slope]

(3)
First, solve for slope.
Formula for slope: $\frac{y2-y1}{x2-x1}$
Plug in values: $\frac{-1-5}{-4-7} = - \frac{6}{11}$
Slope: $- \frac{6}{11}$
Second, we must plug into point-slope form.
Formula for point-slope: $y - y1 = m(x-x1)$
Plug in the values: $y + 1 = - \frac{6}{11}(x + 4)$ {Choice C}

(4)
First, solve for slope.
Formula for slope: $\frac{y2-y1}{x2-x1}$
Plug in values: $\frac{6-(-8)}{-4-7} = - \frac{14}{11}$
Slope: $- \frac{14}{11}$
Second, we must plug into point-slope form.
Formula for point-slope: $y - y1 = m(x-x1)$
Plug in the values: $y - 6 = - \frac{14}{11}(x + 4)$ {Choice D}

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3 years ago

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