The possible values for the third side's measurement are3 < x < 17. Any two sides of a triangle's lengths added together must be longer than the third side.
<h3>How do you determine a triangle's perimeter?</h3>
- The third side of a triangle must always have a length that is between (but not exactly) the sum and the difference of the other two sides.
- Any two sides of a triangle's lengths added together must be longer than the third side.
- Each side of a triangle with sides a, b, and c must fall within the difference and total of the other two.
- For instance, side a must be between b-c and b+c or b-cab+c.
- The third side must fall between 10 -7 = 3 and 10 + 7 = 17.
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Answer:
0.8181818
Step-by-step explanation:
3/11×3 = 0.8181
49^(3/2)
This is the same as (sqrt49)^3
7^3 = 343
Answer:
<u> BC = 10 and AD = 30</u>
Step-by-step explanation:
In figure-1 , AB = CD ,BK ⊥ AD, AK = 10, KD = 20.
Since, line AD is sum of AK and KD, then
AD = AK + KD
AD = 10 + 20
AD = 30
Since, BC ║AD and BK ⊥ AD then similarly we construct CL ⊥ AD
so, BC = KL and AK = LD
KL = AD - LD
KL = 20 - 10
KL = 10
Since, BC = KL then BC = 10
Hence, <u> BC = 10 and AD = 30</u>
Answer:
BC = 28
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Step-by-step explanation:
Given that the triangles are similar then the ratios of corresponding sides are equal, that is
=
, substitute values
=
( cross- multiply )
12BC = 340 ( divide both sides by 12 )
BC =
=
= 28 