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3 years ago

The table represents an exponential function.

1 answer:

4 0

Hello,
$f(1)=2\\
f(2)= \dfrac{2}{5} =2*5^{-1}\\
f(3)= \dfrac{2}{25} =2*5^{-2}\\
f(4)= \dfrac{2}{125} =2*5^{-3}\\\\

\boxed{f(x)= 2*5^{-x}} \\


$

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3 years ago

Find the area of the figure

uranmaximum [27]

Answer:

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Step-by-step explanation:

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2 years ago

How do u factor this

PilotLPTM [1.2K]

You can factor a parabola by finding its roots: if

$p(x)=x^2+bx+c$

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In order to find the roots, you can use the usual formula

$x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

In the first example, this formula leads to

$x_{1,2} = \dfrac{-2\pm\sqrt{4+4}}{2} = \dfrac{-2\pm\sqrt{8}}{2} = \dfrac{-2\pm2\sqrt{2}}{2} = 1 \pm \sqrt{2}$

So, you can factor

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The same goes for the second parabola.

As for the third exercise, simply plug the values asking

$f(1.5)=-5.25$

you get

$f(-1.5) = 1.5c-3 = -5.25$

Add 3 to both sides:

$1.5c = -2.25$

Divide both sides by 1.5:

$c = 1.5$

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3 years ago

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Answer:

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago