Question

Geometry Homework ( SOH CAH TOA ) PLEASE HELP!!

Answer 1

Answer:

Question 3:

AC = 3 yd.

m∠B = 37°

m∠C = 53°

Question 4;

GH = 8 km.

m∠H = 62°

m∠I = 28°

Step-by-step explanation:

Question 3:

The length AC

$AC = 5*sin B.$

And the angle B

$\boxed{\angle B=cos^{-1}(\frac{4}{5} )=36.87^o\approx 37^o.}$

Therefore

$\boxed{AC = 5*sin(37^o)= 3yd}$

And the angle C:

$\boxed{\angle C=sin^{-1}(\frac{4}{5} )=53.13^o \approx 53^o}$

Question 4:

The side GH

$GH =17\:sin(I)$

The angle I is

$\boxed{\angle I=cos^{-1}(\frac{15}{17} )=28.07^o\approx 28^o}$

Therefore,

$\boxed{GH =17\:sin(I)=17sin(28^o)=8km}$

And the angle H:

$\boxed{\angle H=sin^{-1}(\frac{15}{17} )=61.927^o\approx 62^o}$