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2 years ago

What ratios are equivalent to 4:3? 7:2 12/42 28:21 42:12

Mathematics

1 answer:

Karolina [17]2 years ago

3 0

28:21

because the same number has to multiply both sides of the ratio. so number = 7 and:
4x 7 = 28
3 x 7 = 21

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Can anyone help me ASAP!

Stells [14]

Answer:

154m

Step-by-step explanation:

You do: 19+7=26

180-26=154

That is how you get the answer

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2 years ago

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What is the surface area for the given figure?

icang [17]

The formula of the surface area of any prism is,

Ph + 2B

P = 10 + 24 + 26 = 60

B = area

B triangle = ½ bh

B triangle = ½ 24 × 10 = 120

So,

60 × 34 + 2(120) = 2,280 cm²

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Answer : 2,280 cm²

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I hope that helps you out!!

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2 years ago

Suppose integral [4th root(1/cos^2x - 1)]/sin(2x) dx = A<br>What is the value of the A^2?<br><br>

Alla [95]

$\large \mathbb{PROBLEM:}$

$\begin{array}{l} \textsf{Suppose }\displaystyle \sf \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx = A \\ \\ \textsf{What is the value of }\sf A^2? \end{array}$

$\large \mathbb{SOLUTION:}$

$\!\!\small \begin{array}{l} \displaystyle \sf A = \int \dfrac{\sqrt[4]{\frac{1}{\cos^2 x} - 1}}{\sin 2x}\ dx \\ \\ \textsf{Simplifying} \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\sec^2 x - 1}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt[4]{\tan^2 x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sqrt{\tan x}}{\sin 2x}\cdot \dfrac{\sqrt{\tan x}}{\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\tan x}{\sin 2x\ \sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{\sin x}{\cos x}}{2\sin x \cos x \sqrt{\tan x}}\ dx\:\:\because {\scriptsize \begin{cases}\:\sf \tan x = \frac{\sin x}{\cos x} \\ \: \sf \sin 2x = 2\sin x \cos x \end{cases}} \\ \\ \displaystyle \sf A = \int \dfrac{\dfrac{1}{\cos^2 x}}{2\sqrt{\tan x}}\ dx \\ \\ \displaystyle \sf A = \int \dfrac{\sec^2 x}{2\sqrt{\tan x}}\ dx, \quad\begin{aligned}\sf let\ u &=\sf \tan x \\ \sf du &=\sf \sec^2 x\ dx \end{aligned} \\ \\ \textsf{The integral becomes} \\ \\ \displaystyle \sf A = \dfrac{1}{2}\int \dfrac{du}{\sqrt{u}} \\ \\ \sf A= \dfrac{1}{2}\cdot \dfrac{u^{-\frac{1}{2} + 1}}{-\frac{1}{2} + 1} + C = \sqrt{u} + C \\ \\ \sf A = \sqrt{\tan x} + C\ or\ \sqrt{|\tan x|} + C\textsf{ for restricted} \\ \qquad\qquad\qquad\qquad\qquad\qquad\quad \textsf{values of x} \\ \\ \therefore \boxed{\sf A^2 = (\sqrt{|\tan x|} + c)^2} \end{array}$

$\boxed{ \tt \red{C}arry \: \red{ O}n \: \red{L}earning} \: \underline{\tt{5/13/22}}$

4 0

2 years ago

What is 1/2 of 7/10

Vsevolod [243]

Answer:

7/20

Step-by-step explanation:

of = multiply

1/2 x 7/10

1 x 7 = 7

2x 10 = 20

7/20 can not be reduced.

so, the answer will be 7/20

<h2><u><em>hope it helps </em></u></h2>

3 0

3 years ago

X+13/2=4 what x equal

Harlamova29_29 [7]

Step-by-step explanation:

x+13÷2×2=4×2

x+13=8

x+13-13=8-13

x=8-13

x=-5

7 0

3 years ago

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