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Nitella [24]
3 years ago
12

Pleaaseeeee helpppp ASAPPPP

Mathematics
1 answer:
WINSTONCH [101]3 years ago
4 0

Answer:

It would be 11

Step-by-step explanation:

If you look at the 2 x 11 = 22

and that goes on with it on 7 and 9.

Hope this helps!!

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The tree in chucks yard is 48 feet tall. How many inches tall is the tree
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Step-by-step explanation:

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2 years ago
WHAT IS THE REMAINDER WHEN <img src="https://tex.z-dn.net/?f=32%5E%7B37%5E%7B32%7D%20%7D" id="TexFormula1" title="32^{37^{32} }"
Feliz [49]

Recall Euler's theorem: if \gcd(a,n) = 1, then

a^{\phi(n)} \equiv 1 \pmod n

where \phi is Euler's totient function.

We have \gcd(9,32) = 1 - in fact, \gcd(9,32^k)=1 for any k\in\Bbb N since 9=3^2 and 32=2^5 share no common divisors - as well as \phi(9) = 6.

Now,

37^{32} = (1 + 36)^{32} \\\\ ~~~~~~~~ = 1 + 36c_1 + 36^2c_2 + 36^3c_3+\cdots+36^{32}c_{32} \\\\ ~~~~~~~~ = 1 + 6 \left(6c_1 + 6^3c_2 + 6^5c_3 + \cdots + 6^{63}c_{32}\right) \\\\ \implies 32^{37^{32}} = 32^{1 + 6(\cdots)} =  32\cdot\left(32^{(\cdots)}\right)^6

where the c_i are positive integer coefficients from the binomial expansion. By Euler's theorem,

\left(32^{(\cdots)\right)^6 \equiv 1 \pmod9

so that

32^{37^{32}} \equiv 32\cdot1 \equiv \boxed{5} \pmod9

7 0
2 years ago
Math questions. Correct please
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Hope this helps out! :)


8 0
3 years ago
Find an ordered pair (x y) that is a solution to the equation calculator
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So your answer will be 6,2.

Another answer to your question would be 4,1.
7 0
3 years ago
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