Question

You have a 12 sided cube that is numbered from 1 to 12. What is the probability of rolling a 5?

Answer 1

Answer:

$p(E)=\frac{1}{12}$

Explanation:

Given:

Side of the cube = 12

event = 5

Solution:

Using probability formula.

$p(E)=\frac{n(E)}{n(S)}$

Where:

p(E) = Probability of an event

n(E) = Favourable event

n(S) = Sample space

Sample space of a 12 sided cube that is numbered from 1 to 12.

Sample space = {1,2,3,4,5,6,7,8,9,10,11,12}

$n(S)=12$

Favourable event = {5}

$n(E) = 1$

So the probability of rolling a 5.

$p(E)=\frac{1}{12}$

Therefore, the probability of rolling a cube for event 5 is $p(E)=\frac{1}{12}$