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Trava [24]
3 years ago
6

The diameter of a planet is about 10,652 mi. The diameter of the planet's moon is about 25% of the planet. What percent of the v

olume is the volume of its moon.
*ROUND TO THE NEAREST WHOLE NUMBER AS NEEDED.
Mathematics
1 answer:
alekssr [168]3 years ago
5 0

Answer:

2\%

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x----> the volume of  the planet's moon

y---> the volume of the planet

so

z^{3}=\frac{x}{y}

In this problem we have

z=0.25

elevated to the cube

z^{3}=0.25^{3}=0.015625

Find the percent

0.015625*100=1.56\%

Round to the nearest whole number

1.56\%=2\%

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Step-by-step explanation: No. Ari should have written the percent ratio as 5/100

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Three times a larger number is 30 more than 5 times a smaller number. The sum of the larger number and 5 times the smaller numbe
slava [35]
3y  = 5x + 30

y + 5x = 50 .......(1)

3y - 5x = 30 .....(2)        - rearranging the first equation.

Add (1) and (2):-

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slava [35]

9514 1404 393

Answer:

  A: (3x +4)

  B: (4x +5y) × (4x -5y)

Step-by-step explanation:

<u>Part A</u>:

Since we know the trinomial is a perfect square, we know the terms of each binomial factor are the square roots of the first and last terms of the trinomial.

  9x² +24x +16 = (√(9x²) +√16)² = (3x +4)²

The side of the square is 3x+4.

__

<u>Part B</u>:

The difference of squares is factored like this:

  a²-b² = (a +b)(a -b)

The given area expression is the difference of squares with ...

  a = 4x, b = 5y

so, the factorization is ...

  16x² -25y² = (4x +5y)(4x -5y)

The dimensions of the rectangle are (4x+5y) by (4x-5y).

3 0
3 years ago
"a u.S. 1-cent coin (a penny) has a diameter of 19 mm and a thickness of 1.5 mm". Assume the coin is made of pure copper, whose
choli [55]

<u>the question is </u> Calculate the value of the copper in the coin

Step 1

Find the volume of the coin

we know that

the volume of a cylinder is equal to

V=\pi r^{2}h

where

r is the radius of the coin

h is the thickness of the coin

in this problem we have

Diameter=19 mm=1.9 cm

r=D/2------> r=1.9/2=0.95 cm

h=1.5 mm=0.15 cm

substitute the values in the formula

V=\pi*0.95^{2}*0.15=0.425\ cm^{3}

Step 2

<u>Find the mass of copper in the coin</u>

we know that

the density is equal to

Density=mass/volume

Solve for the mass

mass=Density*volume

we have

Density=8.9\ gr/cm^{3}\\Volume=0.425\ cm^{3}

substitute in the formula

mass=8.9*0.425=3.785\ gr

Step 3

<u>Find the cost</u>

we know that

the market price of the copper is $2.15 per pound

1 pound=453.592 grams

convert gram to pounds

3.785 gr=3.785/453.592=0.0083 pounds

0.0083*$2.15=$0.018=$0.02

therefore

<u>the answer is</u>

$0.02

3 0
3 years ago
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