In the circle below, suppose m STQ = 102° and mZTSR=56º. Find the following.
1 answer:
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Ball hit the ground is when the function equals zero
0=-16t^2+46t+6
we can't factor so use quadraticformula
for
ax^2+bx+c=0
x=
x=
x=
x=
x=
x=
or 
x=
or x=
x=-1/6 or x=3
we cannot have negative time because time starts at 0
disregard -1/6 as a possible answer
answer is after 3 seconds
0=-16t^2+46t+6
we can't factor so use quadraticformula
for
ax^2+bx+c=0
x=
x=
x=
x=
x=
x=
x=
x=-1/6 or x=3
we cannot have negative time because time starts at 0
disregard -1/6 as a possible answer
answer is after 3 seconds