3 years ago

What is the vertex form of f(x)=x^2+24x+138

Mathematics

2 answers:

Gre4nikov [31]3 years ago

8 0

F(x) = x^2 + 24x + 138
f(x) = x^2 + 24x + (24/2)^2 + 138 - (24/2)^2
f(x) = (x+12)^2 - 6

Veronika [31]3 years ago

6 0

Answer:

(x +12)^2 - 6

Step-by-step explanation:

d/dx x^2 + 24x + 138 = 2x + 24

when 2x + 24 = 0, the gradient = 0

x = -12

f(-12) = -6

therefore we have (x +12)^2 - 6.

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