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3 years ago

Can anyone answer this question please?

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

4 0

When comparing the slopes of the functions you must first make y the subject of formula.

6x - y - 2 = 0 => y = 6x - 2 => slope is 6

2y = 3/2 x + 6 => y = 3/4 x + 3 => slpoe = 3/4

5 = 2x + 4y - 3 => 4y = -2x + 5 + 3 = -2x + 8 => y = -1/2 x + 2 => slope = -1/2

The first function is steepest followed by the second function and then the third function.

The slope is not affected by the y-intercept neither is the y-intercept affected by the slope.

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BC and DF are parallel lines. B is a point on AD and E is a point of DF. BD=BE. work out angle DBE give a reason. ITS ON MATHSWA

zloy xaker [14]

Answer:

(Angle DBE) ∠DBE = 50°

Step-by-step explanation:

It is crucial for us to be able to interpret plane geometry related question in order to solve them efficiently.

From the question given; we have analysed and come up with a diagrammatic expression and mathematical solution that clearly explains the question .

Given that

BC and DF are parallel lines.

B is a point on AD

BD=BE

work out angle DBE and give a reason.

The diagram can be seen in the attached image below.

SInce ∠BD = ∠DE

Then triangle BDE is an isosceles triangle. In an isosceles triangle ; two sides are equal in length.

The sum of angles in an isosceles triangle = 180° (sum of angles in a triangle)

So;

∠BDE + ∠BED + ∠DBE = 180° (sum of angles in a triangle)

From the diagram; we will see that ∠ABC = ∠BDE (corresponding angle)

Since ; ∠ABC is not given and which is needed to solve this question.

Let's just assume that ∠ABC is 65° , the main thing is to be able to interpret and understand the concept of the question.

Now;

Since

∠ABC = ∠BDE

∠ABC = 65°

∠BDE = 65°

Again;

∠BDE + ∠BED + ∠DBE = 180° (sum of angles in a triangle)

∠BDE will be aso equal to ∠BED ; this is because since the length of the opposite sides of the isosceles triangle are equal, their angles will also be equal.

Therefore;

65° + 65° + ∠DBE = 180° (sum of angles in a triangle)

130 ° + ∠DBE = 180° (sum of angles in a triangle)

∠DBE = 180° - 130°

∠DBE = 50°