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san4es73 [151]
3 years ago
12

P-1=5p+3p-8 how do I solve this?

Mathematics
2 answers:
erica [24]3 years ago
8 0
p-1=5p+3p-8\\ \\p-8p=-8+1\\ \\-7p=-7\ \ /:(-7)\\ \\p=1
Viktor [21]3 years ago
6 0
P-1=8p-8
Add 1 to both sides
p=8p-7
Subtract 8p from both sides
-7p=-7
Divide by -7
p=1
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Y=5x+4 and 3x+2y=20 by using elimination​
nikklg [1K]

Answer:

Step-by-step explanation:

 y = 5x + 4

-5x + y = 4 ----------------------(i)

3x + 2y = 20 --------------------(ii)

Multiply equation (i) by (-2)

(i)* (-2)     10x - 2y = -8

(ii)            <u>3x   + 2y = 20</u>    { Now add this two equations}

              13x           = 12      { -2y and 2y got eliminated}

                          x = 12/13

Plug in value of x in (i)

-5*12/13  + y = 4

-60/13 + y = 4

y = 4 + 60/13

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5 0
3 years ago
Y = 3x + 15<br> 3x + 3y = 9
Zina [86]

Answer:

\Large\boxed{x=-3}\Large\boxed{y=6}

Step-by-step explanation:

<u>Given the system of equations</u>

1)~y=3x+15

2)~3x+3y=9

<u>Divide 3 on both sides of the 2) equation</u>

3x+3y=9

3x\div3+3y\div3=9\div3

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<u>Current system</u>

1)~y=3x+15

2)~x+y=3

<u>Substitute 1) equation into the 2) equation</u>

x+(3x+15)=3

<u>Combine like terms</u>

x+3x+15=3

4x+15=3

<u>Subtract 15 on both sides</u>

4x+15-15=3-15

4x=-12

<u>Divide 4 on both sides</u>

4x\div4=-12\div4

\Large\boxed{x=-3}

<u>Substitute the x value into one of the equations to find the y value</u>

y=3x+15

y=3(-3)+15

y=-9+15

\Large\boxed{y=6}

Hope this helps!! :)

Please let me know if you have any questions

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nika2105 [10]

Answer:

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Step-by-step explanation:

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