(-5,-10)E
(-5,-3)F
(-3,-10)G
BD = AC/2
4x+2 = (5x+13)/2
2(4x+2) = 5x+13
8x + 4 = 5x+13
8x - 5x = 13 -4
3x = 9
x = 3
I think p=4
How I solved it:
5(-2)+2p+2(-1)=2p
-10+2p+-2=2p So cross out last
-2p -2p 2p:)
= -10+2p+-2
+10 +10 Cross out the 10
= 2p=8
= divide both sides by 2p
= 2p/2= 8/2
= cross out the 2.
= which leaves
= p=4 we get 4 because we divide 8 to 2:)
I don’t know if I’m right but yea...
15) 4m^2
17)9n^6
198a^2 (^ = power of)
Answer:
The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Find the highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10%.
This is the 10th percentile, which is X when Z has a pvalue of 0.1. So X when Z = -1.28.




The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.