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4 years ago

9

Nadine can send or receive a text message for 15 cents or get an unlimited number for 5 dollars. Write and solve an inequality t

o find how many messages she can send and receive so the unlimited plan is cheaper than paying for each message.

1 answer:

Ne4ueva [31]4 years ago

4 0

$0.15x>$5.00
x>33.3333
So if she sends or receives more than 33 text messages, she will be paying more than $5.00.

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A customer at Lost Pastores placed an order for 3 burritos which was priced at x amount of dollars each. He also ordered a plate

timofeeve [1]

Answer:

3x +12.95 = 32.46

Step-by-step explanation:

3 burritos plus x + 12.95 = $32.46

3 0

3 years ago

Read 2 more answers

The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m

castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean of 10 minutes:

This means that $m = 10, \mu = \frac{1}{10} = 0.1$

A. What is the probability that the arrival time between customers will be 7 minutes or less?

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)$

$P(X \leq x) = 1 - e^{-\mu x}$

$P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034$

$P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592$

$P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442$

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

3 0

3 years ago

(1.5 x 10^2) X (2.0 x 10^3) Express your answer in scientific notation and standard form.

zavuch27 [327]

Answer:

3*10^5 or 300,000 cant remember witch one it is

Step-by-step explanation:

1.5*10^2= 150

2*10^3=2,000

150*2000=300,000

3*10^5

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3 years ago

Yoko buys candy that costs $8 per pound. She will spend $40 on candy. What are the possible numbers of pounds she will buy?

sergiy2304 [10]

Answer:

5pd

Step-by-step explanation:

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3 years ago

If the simple interest rate is 5%p.a. , how long does it take for the amount to become twice the principal

solong [7]

A = P + I
2a = a + PTR/100
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2=1+T/20
T=20 yrs

3 0

3 years ago