Answer:
Perimeter of the figure = 198.54 feet
Step-by-step explanation:
Given figure comprises a rectangle and two semicircles.
Perimeters of two semicircle = 2πr
Here 'r' = Radius of the circle
Perimeter of two semicircles at the sides of the rectangle = 
= 25π feet
= 78.54 feet
Length of side AB = Length of side CD = 60 feet
Perimeter of the given figure = 2(60) + 78.54
= 198.54 feet
the answer is 0.2 or one fifths
Step-by-step explanation:
remember. the radius is always half the diameter.
volume of a cylinder
pi × r² × height
pi×7.5²×48 = pi×56.25×48 = 8,482.300165... in³
volume of a sphere
4/3 × pi × r³
and that volume should be the same as the cylinder. so,
4/3 × pi × r³ = pi×56.25×48
4/3 × r³ = 56.25 × 48
1/3 × r³ = 56.25 × 12
r³ = 56.25 × 36 = 7.5² × 6² = (7.5×6)² = 45² = 2025
![r = \sqrt[3]{2025}](https://tex.z-dn.net/?f=r%20%3D%20%20%5Csqrt%5B3%5D%7B2025%7D%20)
which would be 12.65148998... in.
Well, 5384 is 5000 bigger than 384. So you would add 20000 (4*5000) to the answer of 4*384, which is 1536.
So 1536+20000=21536