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joja [24]
3 years ago
6

5. An airplane takes 4 hr to travel a distance of 4100 km. Another airplane travels at a speed

Mathematics
1 answer:
Mazyrski [523]3 years ago
7 0

Answer:

4.969696 hours

Step-by-step explanation:

The distance traveled is shown through the following equations

Distance = velocity * time

This means that

4100=velocity*4

This means that ariplane 1 travles at 1025 km/hr

We can then subtract 200 from this to find that airplane two travels at a speed of 825 km/hr

Now we need to find how long it takes for that plane to travel 4100

So using the same equation

4100=825*time

Divison will tell us that the answer is around 4.9696 hours which is pretty much 5

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Write the expression. Then, check all that apply. twice the difference of a number and six A 2-column table with 4 rows. Column
Pie

The statements that apply to the algebraic expression are

  • Replace “a number” with the variable, n.
  • The two operations are multiplication and subtraction.
  • The constants are 2 and 6.
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<h3 /><h3>How to determine the algebraic expression?</h3>

The complete question is added as an attachment

The statement is given as:

Twice the difference of a number and six

Represent the number with n.

So, the statement becomes

Twice the difference of a n and six

Twice means 2 *

So, we have

2 * difference of a n and six

Express difference as minus i.e. -

So, we have

2 * (n - 6)

Hence, the expression is written as 2(n - 6)

Read more about algebraic expressions at:

brainly.com/question/4344214

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Angle 3 and angle 4 are supplementary angles. Angle 3 is 88°. What is the measure of angle 4?
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