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IRISSAK [1]
3 years ago
8

What is the difference between a linear function and a nonlinear function? Explain what each looks like when represented as a ta

ble and as a graph.
Mathematics
2 answers:
Ivenika [448]3 years ago
7 0

Answer:

On a graph, it is easy to remember whether a function is linear or nonlinear. Nonlinear means the graph is not a straight line. The graph of a nonlinear function is a curved line. If it is straight, then it is linear. On a table, you can determine whether a function, in tabular form, is nonlinear by observing that the jump in y varies for each unit of change in x.

Step-by-step explanation:

This is NOT the sample response. Please do not use the sample response as it is not the actual answer and teachers may find out you are not using your own responses.

Degger [83]3 years ago
6 0

Answer:

<h3>Sample Answer:<em> </em></h3><h3><em>A linear function has a constant rate of change, while a nonlinear function does not. For a table of values to be linear, the outputs must have a constant rate of change as the inputs increase by 1. On a graph, the function must be a straight line to be linear.</em></h3>

<em />

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Answer:

  1. $4.65
  2. $69.75

Step-by-step explanation:

How much money she makes from each bracelet:

9-4.35=$4.65

How much money she makes from the 15 bracelets:

4.65 x 15= $69.75

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3 years ago
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Cat+Cat+Cat=15
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5 0
3 years ago
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Evaluate the expression when x = 24 and p = -4.
Stels [109]

Answer:

The correct answer is 3. -88

Step-by-step explanation:

24 / 3 + 24 x -4

24 x -4 = -96

24 / 3 = 8

8 + -96 = -88

6 0
2 years ago
Find the sine and cosine of each angle as a fraction and as a decimal. Round to the nearest hundredth.
lawyer [7]

Answer:

<em>1st triangle:</em>

sin(C): 0.64, \frac{16}{25}

cos(C): 0.8, \frac{4}{5}

<em>Second triangle:</em>

sin(C): 0.75, \frac{\sqrt{5} }{3}

cos(C): 0.67, \frac{2}{3}

Step-by-step explanation:

Using SOH CAH TOA, we know that to find the sin of an angle, it's Opposite/Hypotenuse.

To find the cos of an angle, it's adjacent/hypotenuse.

<u>In the 1st triangle:</u>

The adjacent to C is 16, the hypotenuse is 25.

\frac{16}{25} = 0.64 is the sin of C.

The adjacent to C is 20, and the hypotenuse is 25.

\frac{20}{25} = 0.8 is the cos of C.

<u>In the second triangle:</u>

The opposite to C is \sqrt{5} and the hypotenuse is 2.

\frac{\sqrt{5} }{2}  \approx0.75 is the sin of C.

The adjacent to C is 2 and the hypotenuse is 3.

\frac{2}{3} \approx 0.67 is the cos of C.

Hope this helped!

3 0
3 years ago
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Carol is driving at 25 km/h when she sees a stop light turn yellow. If it takes her 1.2 s to begin braking, and the car's accele
I am Lyosha [343]

Answer:

The total distance she travels from the time she first sees the light turn until the car stops is 6.02 meters

Step-by-step explanation:

The car when Carol begins to hit the brakes is traveling with constant deceleration, that means we have to use uniformly accelerated motion equations to solve for the distance traveled, but first we need to analyze the given data.

Given information

  • Initial velocity,  v_i = 25 km/h
  • Final velocity,  v_f = 0
  • Time, t = 1.2 s
  • Acceleration, a= -4.0 \cfrac{m}{s^2}

Almost all information is on standard units except the initial velocity, so we can convert it to meters per second.

v_i = 25 \cfrac{km}{h} \times \cfrac{1h}{3600s}\times \cfrac{1000m}{1km}\\v_i=6.94 \cfrac ms

Also notice that the final velocity is 0 m/s, since the car stops at the end.

Setting up the motion equation.

Since we have constant acceleration and since the goal is to find the distance we can use the following equation for uniformly accelerated motion.

v_f^2 = v_i^2 +2ad

Here d is the distance traveled, replacing the given information we get

0=\left(6.94 \cfrac ms\right)^2 +2\left( -4 \cfrac{m}{s^2}\right)d

Solving for d

We can solve for the distance traveled d by moving every other number to the other side.

-\left(6.94 \cfrac ms\right)^2 =2\left( -4 \cfrac{m}{s^2}\right)d

We can divide both sides by -8

\cfrac{6.94^2}{8} m= d

So we get

\boxed{d=6.02     m}

The car has traveled 6.02 meters before stopping.

3 0
3 years ago
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