Question

A parallelogram has sides measuring 23.8 m and 35.3 m. The height corresponding to the 23.8-m base is 9.9 m. Find the height, to the nearest tenth of a meter, corresponding to the 35.3-m base.

Answer 1

Answer:

The value of x i.e DE is $6.7m^2$

Step-by-step explanation:

Given a parallelogram has sides measuring 23.8 m and 35.3 m. The height corresponding to the 23.8-m base is 9.9 m. we have to find the height corresponding to the 35.3-m base which is DE

Area of parallelogram ABCD=$Base AB\times heightDE$

                                               =$35.3\times x$

                                               =$35.3x m^2$

Area of parallelogram ABCD=$Base BC\times heightDF$

                                               =$23.8\times 9.9$

                                               =$235.62 m^2$

Above two is the area of same parallelogram

⇒ $35.3x=235.62$

⇒  $x=6.6747\sim6.7m^2$

Hence,The value of x i.e DE is $6.7m^2$