An ulcer patient has been told to avoid acidic foods. If he drinks coffee, with a pH of 5.0, it bothers him, but he can tolerate
both tap water, with a pH of 5.8, and milk, with a pH of 6.9 .In order to make 10 oz of a milk-coffee drink with a pH of 5.8, how many ounces of each are required?
The equation should look like : [H+] = (1-a)(x) + (a)(y) Where: 5.8 = -log [H+] 5.0 = -log x 6.9 = -log y (1-a) = proportion of x <span>a = proportion of y so calculating a will give you the result of how many ounces are required</span>
