Ask question

Ask question

All categories

3 years ago

9

An ulcer patient has been told to avoid acidic foods. If he drinks coffee, with a pH of 5.0, it bothers him, but he can tolerate

both tap water, with a pH of 5.8, and milk, with a pH of 6.9 .In order to make 10 oz of a milk-coffee drink with a pH of 5.8, how many ounces of each are required?

1 answer:

kirill [66]3 years ago

3 0

The equation should look like :
[H+] = (1-a)(x) + (a)(y)
Where:
5.8 = -log [H+]
5.0 = -log x
6.9 = -log y
(1-a) = proportion of x
<span>a = proportion of y
so calculating a will give you the result of how many ounces are required</span>

You might be interested in

The following steps are used to rewrite the polynomial expression x(x-5y) 2y (x-5y

Mice21 [21]

$2x^3y-20x^2y^2+50xy^3$

8 0

3 years ago

Please help me with 11-16 please! Thank you

sasho [114]

11. -1

12. -9

13. 32

14. -15

15. 10

16. 24

3 0

3 years ago

In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

Viktor [21]

Answer:

$p_v =P(t_{(63)}>2.5)=0.0075$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=45$ represent the mean height for the sample

$s=16$ represent the sample standard deviation for the sample

$n=64$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=64-1=63$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(63)}>2.5)=0.0075$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

6 0

3 years ago

What is the value of x when -3x + 7x = -12?

Natalka [10]

-3 + 7x = -12

First, simplify -3x + 7x to get 4x. / Your problem should look like: 4x = -12
Second, divide both sides by 4. / Your problem should look like: x = $- \frac{12}{4}$
Third, simplify $\frac{12}{4}$ to 3. / Your problem should look like: x = -3

Answer: x = -3

4 0

4 years ago

Read 2 more answers

What is the value of x? <br><br><br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B5%7D%20x%20-%20%20%5Cfrac%7B1%7D%7B10%

NeTakaya

Answer:

x = $\frac{1}{2}$

Step-by-step explanation:

Given

$\frac{4}{5}$ x - $\frac{1}{10}$ = $\frac{3}{10}$

Multiply through by 10 ( the LCM of 5 and 10 ) to clear the fractions

8x - 1 = 3 ( add 1 to both sides )

8x = 4 ( divide both sides by 8 )

x = $\frac{4}{8}$ = $\frac{1}{2}$

6 0

3 years ago