The surface area of a cylinder is define by the formula S.A.=2πrh+2<span>πr^2, where the first part of the formula refers to the lateral area, perimeter, or circumference and the second part to the area of the bases, which are circles.
On this exercise it is asked to find the lateral area of a cylinder whose radius is 6 cm, and has a height of 20cm. To find the lateral area of the cylinder you should substitute this values into the formula, S.A.=2</span>πrh, and as can be seen the answers are given in terms of <span>π or pi.
S.A.=2</span><span>πrh
S.A.=2</span><span>π(6cm)(20cm)
S.A.=2</span><span>π(120cm)
S.A.=240</span>π cm^2
The lateral area of the cylinder is 240<span>π cm^2 or in other words letter B from the given choices.</span>
(x^2 +3)(5x+9)
5x^3 + 9x^2 + 15x + 27
You just need to foil. 2x times 4x times 2x times 36 times 24 times 4x times 24times 36. then solve.
Answer: z + 17
Step-by-step explanation:
1) DISTRIBUTE:
11 + 2z + 6 - z
2) COMBINE LIKE TERMS
z + 17
<span>The solution to the equation 2/3 A= -24 is the coordinate of point A.
2/3 A = -24
A = -24 / 2/3
A = -24 * 3/2
A = -72/2
A = -36
The solution to the equation 20=-b/0.5 is the coordinate of point B
20 = -b/0.5
20 * 0.5 = -b
10 = -b
10/-1 = -b/-1
-10 = b
A = -36 and B = -10
The distance between the two letters is 26 units. </span>
