Answer:
Step-by-step explanation:
lets replace x with 3
f(3)= -2(3)^3+3(3+2)=-2*27+15=-54+15=-39
The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>
The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using

Substitute the known values in the above equation

Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
Read more about distance at
brainly.com/question/1872885
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A boy swimming at an elevation of 3 feet below sea level. This is the answer because the boy is only 3 feet away from sea level while the bird is 10 feet away form sea level.
Split it up
3x^2+12x-5x-20
group
(3x^2+12x)+(-5x-20)
factor
(3x)(x+4)+(-5)(x+4)
undistribute (x+4) like ab+ac=a(b+c)
(3x-5)(x+4)
Answer:
dee y by dee x
Step-by-step explanation: hope this helps! have a supercalifragilisticexpialidocious day! ◑﹏◐