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2 years ago

Divide and answer in simplest form:

Mathematics

2 answers:

Black_prince [1.1K]2 years ago

7 0

5/3*1/3
5*1=5 and 3*3=9
5/9<span><span>c</span></span>

Arturiano [62]2 years ago

6 0

5/3 divide by 3 would be 5/9 so your answer would be C) 5/9.

5/3 * 1/3

5 * 1 over 3 * 3

5 over 3 * 3

So in total the answer would be C) 5/9.

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9/20

NISA [10]

For this case we must find the solution of the following quadratic equation:

$x ^ 2 + 5x + 7 = 0$

Where:

$a = 1\\b = 5\\c = 7$

Then, the solution is given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Substituting the values:

$x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}$

By definition we have: $i ^ 2 = -1$

$x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}$

Thus, we have two complex roots.

Answer:

The equation has no real roots.

4 0

3 years ago

Help math question derivative!

atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

5 0

3 years ago

A 32-oz. Can of spaghetti sauce cost $0.99. Find the unit per ounce to the nearest tenth of a cent.

Nostrana [21]

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4 0

2 years ago

Read 2 more answers

In a triangle, the measure of the first angle is twice the measure of the second angle. the measure of the third angle is 80 de

Furkat [3]

1st angle = 2 * 2nd angle
3rd angle = 2nd angle + 80

1st angle = 2x

2nd angle = x
3rd angle = 80 + x

2x + x + 80 + x = 180
4x = 100
x = 25

1st angle = 50
2nd angle = 25
3rd angle = 105

3 0

3 years ago

Find the values of x and y.

DENIUS [597]

X = 20 degrees
Y = 30
This is acute triangle so all the sides and angles are the same. Subtract 16 from 46 and you receive 30 for y. For the corresponding angle, subtract 80 from 180. Then add 60 to that and subtract that from 180 for x.

6 0

2 years ago