When an ion accelerates through a potential difference of 2160 V its electric potential energy decreases by 3.46×10−16 J . What
is the charge on the ion?
1 answer:
We do as follows:
energy = charge x voltage change .
Let q be the charge then E = q V
<span>and solving for q we have
q = E / V = -1.37e-5J / 2850V = -4.81x10-9 C
</span>
Hope this answers the question. Have a nice day.
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