A ball thrown straight up climbs for 3.0 sec before falling. Neglecting air resistance, with what velocity was the ball thrown?
1 answer:
Answer:
Speed, u = 29.4 m/s
Explanation:
Given that, A ball thrown straight up climbs for 3.0 sec before falling, t = 3 s
Let u is speed with which the ball is thrown up. When the ball falls, v = 0
Using first equation of motion as :
v = u + at
Here, a = -g
So, u = g × t
u = 29.4 m/s
So, the speed with which the ball was thrown is 29.4 m/s. Hence, this is the required solution.
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Answer:
Student’s(50 kg) gravitational potential energy if the cliff is 80 m high = 39.2 kJ
Explanation:
Potential energy is given by the expression, PE =mgh, m is the mass, g is the acceleration due to gravity value and h is the height.
Here mass of student, m = 50 kilogram
Height of cliff , h = 80 meter
Acceleration due to gravity =
Potential energy, PE = 50 * 9.8 * 80 = 39200 J
= 39.2 kJ
Student’s(50 kg) gravitational potential energy if the cliff is 80 m high = 39.2 kJ
Complete Question
The uniform purely axial magnetic induction required by the experiment in a volume large enough to accommodate the Lorentz Tube is produced by the Helmholtz Coils. What is the magnetic induction due to a coil current 1.5 Ampere? Convert the result in the still popular non-SI unit Gauss (1 Tesla = 10^4 Gauss).
B = N*mue*I/(2*r)
# of loops = 140
radius of the coil = 0.14m
Answer:
The magnetic induction is
Explanation:
From the question we are told that
The coil current is
The number of loops is
The magnetic field due to the current is mathematically represented as
is the permeability of free space with value
substituting value
From question
(1 Tesla = ).
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