Answer:
678
Step-by-step explanation:
by mulitply
Answer:
—Section 1–
a) 5 points. (Points are the dots, there are 5.)
b) 2 lines. (Line a, line b.)
c) Just 1. (that 2D shape in the background.)
d) VWX (V is in the name.)
e) Point W is the intersection. (Both lines meet at that point, they intersect.)
f) YWZ or ZWY both works (Name the line by its points.)
g) XWZ, XWY, ZWV, etc. (Any 3 points that don’t go in a straight line).
h) YWV, ZWV, YXW, etc. (Any 3 points that are within the same plane.)
—Section 2–
a) 9 points.
b) 3 lines.
c) 2 planes.
d) P, N, G / M, N, O / R, N, S
e) N, T, U, P (Any 4 points that don’t belong in a single plane.)
f) O, N, M / M, N, O
g) Point N.
h) Point C.
i) N, M, U
j) Line D.
—Section 3–
a) 8 points.
b) 9 lines.
c) 5 planes.
d) F, H, C.
e) B, E, F.
f) Line AB.
g) Line EF.
h) Point D.
Answer:
a) 0.62%
b) 518 g
Step-by-step explanation:
a)
Here we want the area under the Normal curve of mean = 500 g and standard deviation s = 10 g to the left of 475 (the probability that the machine produces a box with less than 475 g of cereal).
With the help of a spreadsheet we found that value is 0.0062 or 0.62% (another way of seeing it is that 62 boxes out of 10,000 will have 475 g or less)
<h3>See picture</h3>
b)
Here we want to find a value of such that the area of the Normal curve of mean and standard deviation 10 to the left of 500 is 4% or 0.04
If we make the change
then this is equivalent to finding a value of z for which the area under the Normal curve N(0,1) (mean = 0 s = 1) to the left of z is 4% = 0.04
Either by using a table or spreadsheet, we find that value is z = -1.751
So,
and the manufacturer must set its filling machine to the target weight of 518 g.
Answer:
Step-by-step explanation:
The slope-intercept form of an equation of aline:
<em>m</em><em> - slope</em>
<em>b</em><em> - y-intercept</em>
The formula of a slope:
From the graph we have the points:
(-2, -5)
y-intercept (0, 3) → <em>b = 3</em>
Calculate the slope:
Put the value of the slope and the y-intercept to the equation of a line: