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Evgen [1.6K]
3 years ago
13

Solve this please, and show the work

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0

Answer:

6677766666

Step-by-step explanation:

5tettrhfhyyf was a good relationship is a different person and then use it for the same thing to do in the same thing as possible but you should not be afraid of the person is not a bad person than the other person than the difference between the difference and what you want and you know it would

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When she drives to work, Samantha travels 10 miles in about 15 minutes. Matt travels 23 miles in about 30 minutes. Who has the f
Fantom [35]

Answer:

At 0.77 mi/min, Matt travels faster than Jennifer, who averages

only 0.67 mi/min.

Step-by-step explanation:

Average speed = distance/time

<em>For Samantha, </em>

Average speed = 10/15

Average speed = 0.67 mi/min

<em>For Matt, </em>

Average speed = 23/30

Average speed = 0.77 mi/min

7 0
3 years ago
Solve this problem. -16r=272
adelina 88 [10]

Answer:

-17

Step-by-step explanation:

-16r=272

16r=-272

r=-17

5 0
2 years ago
Read 2 more answers
48million squared.........
lozanna [386]

Answer:

2.304e+15

Step-by-step explanation:

<h2><em>moo</em></h2>
7 0
3 years ago
Compute the directional derivative of the function g(x,y)= sin(π(x−5y)).
e-lub [12.9K]

Answer:

Step-by-step explanation:

The directional derivative of a function in a particular direction u is given as the dot product of the unit vector in the direction of u and the gradient of the function

g(x,y) = sin(π(x−5y)

∇g = [(∂/∂x)î + (∂/∂y)j + (∂/∂z)ķ] [sin(π(x−5y))

(∂/∂x) g = (∂/∂x) sin (πx−5πy) = π [cos(π(x−5y))]

(∂/∂y) g = (∂/∂y) sin (πx−5πy) = - 5π [cos (π(x−5y))]

∇g = π [cos(π(x−5y))] î - 5π [cos (π(x−5y))] j

∇g = π [cos (π(x−5y))] [î - 5j]

So, the question requires a direction vector and a point to fully evaluate this directional derivative now.

8 0
3 years ago
27^x = 9^x − 4 Question 1 options: x = 8 x = 4 x = −4 x = −8
Mariulka [41]

Answer:

x = -8

Step-by-step explanation:

Given the equation:

27^x=9^{x-4}

Note that

27=3^3\\ \\9=3^2,

then

27^x=(3^3)^x=3^{3x}\\ \\9^{x-4}=(3^2)^{x-4}=3^{2(x-4)}

Rewrite the equation as

3^{3x}=3^{2(x-4)},

then

3x=2(x-4)\\ \\3x=2x-8\\ \\3x-2x=-8\\ \\x=-8

4 0
3 years ago
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