Question

Will mark brainliest if you can help me and earn 20pts A party rental company has chairs and tables for rent. The total cost to rent 8 chairs and 4 tables is $ 45 . The total cost to rent 3 chairs and 2 tables is $ 21 . What is the cost to rent each chair and each table?

Answer 1

Answer:

The rent of 1 chair is $1.5 and rent for 1 table is $8.25.

Explanation:

Given:

A party rental company has chairs and tables for rent.  

Let the rent for a single chair be $m and rent for single table be $n.  

The total cost to rent 8 chairs and 4 tables is $ 45 .  

Then, 8 x $m + 4 x $n = $45  8m + 4n = 45  (1)

The total cost to rent 3 chairs and 2 tables is $ 21.

Then, 3 x $m + 2 x $n = $ 21  3m + 2n = 21  (2)  

To find:

what is the cost to rent each chair and each table?

Solution:

let us solve the above two equations.

Equation(1) x 1 ...........  8m + 4n = 45

Equation(2) x 2..........  6m + 4n = 42 [we multiplied with 2 because, then, coefficient of n equals and easy to cancel

8m + 4n = 45

6m + 4n = 42

(-)----------------------------

2m + 0 = 3  

M = $\frac{3}{2}$ = 1.5

Then, substitute m = 1.5 in (1)

8(1.5) + 4n = 45  

12 + 4n = 45  

4n = 45 – 12

4n = 33  

n = 8.25

Hence, the rent of 1 chair is $1.5 and rent for 1 table is $8.25.