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Doss [256]
2 years ago
8

Whats the radius for the circle? x^2+2x+y^2+4y-6=0

Mathematics
1 answer:
MAXImum [283]2 years ago
5 0

Answer:

r = \sqrt{11}

Step-by-step explanation:

So we need to complete the square for both parts of the equation

First though we can add the 6 to the other side so we have x² + 2x + y² + 4y = 6

So first we can complete the square for x² + 2x

To do so we need to use (\frac{b}{2} )^{2} to figure out the number we need to add to both sides

In this case our b is 2, so substituting this in we get (\frac{2}{2} )^{2} =(1)^{2} =1

Here we add 1 to both sides and now we have x² + 2x + 1 + y² + 4y = 6 + 1

Now we can follow the same steps to complete the square for y² + 4y

Here our b is 4, so substituting this in we get (\frac{4}{2} )^{2}=(2)^{2} =4

Now we add 4 to both sides and now we have x² + 2x + 1 + y² + 4y + 4 = 6 + 1 + 4

Now condensing everything we have (x + 1)² + (y + 2)² = 11

The formula for a circle is (x - h)² + (y - k)² = r²

In our equation we have r² = 11

To find the radius we need to take the square root of both sides \sqrt{r^{2}}  =\sqrt{11} to get r = \sqrt{11}

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<u>Explicación:</u>

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Step-by-step explanation:

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2 years ago
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Compare the line passing through the points (−3, −11) and (6, 4) to the line given by the equation y=35x−6.
Aleks04 [339]
Let
<span>A------> (−3, −11)
B------>  (6, 4)

step 1
find the slope m point A and point B
m=(y2-y1)/(x2-x1)-----> </span>m=(4+11)/(6+3)----> m=15/9---> 5/3

step 2
with m=5/3 and point B (6, 4)  find the equation of a line
y-y1=m*(x-x1)-----> y-4=(5/3)*(x-6)---> y=(5/3)x-6

case <span>a. they have the same slope------> is not correct
because
</span><span>y=35x−6------> the slope m=35
</span>y=(5/3)x-6---> the slope m =5/3

case <span>b. they have the same x-intercept.----> is not correct
because
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the x-intercept is the point (6/35,0)

y=(5/3)x-6----> 0=(5/3)x-6----> (5/3)x=6---> x=18/5
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case <span>c. the two lines are perpendicular. do. they have the same y-intercept-----> is nor correct
because

if two lines are perpendicular
m1*m2=-1-------> </span><span>this condition is not satisfied
</span>
the y intercept is for x=0

y=35x−6-------> y=-6
the y intercept is the point (0,-6)

y=(5/3)x-6-----> y=-6
the y intercept is the point (0,-6)

 they have the same y-intercept but the two lines are not perpendicular

see the attached figure

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