The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?
Answer:
Length(L)=22 inches
Width(W) = 7 inches
Step-by-step explanation:
GIven:-
Perimeter (p)=58 inches,
Length(L)= one more than 3 times the width(W)
Let, W=x ---------------------------------(equation 1
-----------------------(equation 2)
Here x is unknown and to find the Width(W) we have to find the value of x.
Now,
Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)
----------------(from equation 1)
----------------(given p=58 inches)
----------------------(equation 3)
Now substituting the value of equation 3 in equation 2.
as, 
-----------------------(from equation 1)
inches -------------------(equation 3)
Therefore, Length(L) = 22 inches and Width(W) = 7 inches.
Answer:
a. (5x-2)-(2x+1)
b. 3x-3
c.39
Step-by-step explanation:
Answer:
2 yards.
Step-by-step explanation:
If you do what was stated in the problem, you would be left at -2. So, you would need to move up 2 yards to get back to 0.
The square root of 5/2 is 2.236067978. The square root of 18 is 4.242640687. The total of 2.236067978 plus 4.242640687= 6.478708667.
If you rounded up to two decimal points. You will get 6.48. It depends what digit your question is telling you to round up to.
Hope it helps.
the only thing you need to do is separate m:
2/7m= 3/14 + 1/7
2/7m= 5/14
m= (5/14)/(2/7)
m= 5/14 × 7/2
m= 35/28
m= 5/4
