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Aleks04 [339]
3 years ago
6

The number f of miles a helicopter is from its destination x minutes after takeoff is given by f (x)=40-2x. The number f of mile

s a commercial jet is from its destination x minutes after takeoff is shown in the graph below.

Mathematics
1 answer:
nevsk [136]3 years ago
7 0

Answer:

Step-by-step explanation:

Function 'f' represents the number of miles (y-values) covered by the helicopter in 'x' (x-values) minutes.

f(x) = 40 - 2x

For x = 0,

f(x) = 40 miles

For f(x) = 0,

0 = 40 - 2x

x = 20 minutes

This shows that helicopter traveled 40 miles in 20 minutes.

Similarly, given graph shows distance covered by the jet on y-axis and duration of flight on x-axis.

For x = 0,

f(x) = 500 miles

For f(x) = 0,

x = 100 minutes

Commercial jet traveled 500 miles in 100 minutes.

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The length of one side of the square base is 8.5 centimeters.

<u>Given the following data:</u>

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To find the length of one side of the square base:

Mathematically, the volume of a cuboid is given by the formula:

Volume = Base \; area × Height

Substituting the given values, we have:

867 = Base \; area × 12

Base\;area = \frac{867}{12}

Base area = 72.225 cm^2

Now, we can find the length by using the formula:

Area \;of\;a \;square = length^2

72.25 = length^2

Length = \sqrt{72.25}

<em>Length</em><em> = </em><em>8.5 centimeters</em>.

Therefore, the length of one side of the square base is 8.5 centimeters.

Find more information: brainly.com/question/11037225

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If y=-5 when x=2,find y when x=8
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3 years ago
180 lb 12 oz - 79.3 kg = ___________ kg
Brrunno [24]

Answer:

180lb\ 12 oz - 79.3kg = 2.8kg

Step-by-step explanation:

Given

180\ lb 12\ oz - 79.3kg

Required

Solve

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Next, convert 12oz to kg

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12oz \to 12 * 0.03kg

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So, the expression becomes:

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Hence:

180lb\ 12 oz - 79.3kg = 2.8kg

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3 years ago
The value of a collectible coin can be represented by the equation Y=2x+15, where x represents its age in years and y represents
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Answer:

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Step-by-step explanation:

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then by substituting 2x=38

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Step-by-step explanation:

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