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mars1129 [50]
3 years ago
10

PLZ HELP MARKIN BRAINIEST!!!

Mathematics
1 answer:
Dahasolnce [82]3 years ago
8 0

From the graph, when x = 1, y = 57,000.

Replace x with 1 in the equations and see if any of the Y 's equal 57,000 :

y = -2610.82(1) + 47860.82 = 45,250

y = 219(1)^2 - 6,506.78(1) + 59,385 = 219 - 6506.78 + 59385 = 53,097.22

y = 54041.5(0.9)^1 =  48,637.35

y = 10,504.6 (1.1)^1 = 11,555.06

The second equation is the closest. so try another x value to see if it is close to the Y value:

Let's try x = 14:

y = 219(14)^2 - 6506.78(14) + 59,385 = 42924 - 91094.92 + 59385 = 11,214.08

This is close to Y = 12,00 shown on the graph

SO the closest equitation is y = 219x^2 - 6506.78x + 59385

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On two investments totaling $11,500, Peter lost 3% on one and earned 4% on the other. If his net annual receipts were $⁢201, how
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Total amount of money invested - $11500
X +Y = $11500. ----------(1)
Total yearly interest for thetwo a/c is - $201
-0.03X + 0.04Y = $201
Form (1)
X = 11500 - Y
Substitute for X
-0.03(11500 - Y) + 0.04 Y = $201
-345 + 0.03Y + 0.04Y =201
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Y = 7800 at 4 %
Calculate X
X = 11500 - Y
= 11500 - 7800
=3700 at - 3%
Check
-0.03×3700 + 0.04 × 7800 = $201
-111 + 312 = $201
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